AP EAMCET · Maths · Circle
The circle touching the \(y\)-axis at a distance 4 units from the origin and cutting off an intercept 6 from \(\mathrm{x}\)-axis is
- A \(x^2+y^2 \pm 10 x-8 y+16=0\)
- B \(x^2+y^2 \pm 5 x-8 y+16=0\)
- C \(x^2+y^2 \pm 5 x-2 y-8=0\)
- D \(x^2+y^2 \pm 2 x-y-12=0\)
Answer & Solution
Correct Answer
(A) \(x^2+y^2 \pm 10 x-8 y+16=0\)
Step-by-step Solution
Detailed explanation
The given situation is possible with the 2 circles. Considering centre at \(C_1\) \(x\) intercept \(=\mathrm{PQ}=6\) \(y\) intercept \(=0\) for \(x^2+y^2+2 g x+2 f y+c=0\) ...(i) \(x\) intercept \(=2 \sqrt{g^2-c}=6\) \(g^2-c=9\) \(y\) intercept \(=2 \sqrt{f^2-c}=0\)…
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