AP EAMCET · Maths · Three Dimensional Geometry
If the two lines \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\) and \(\frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1}\) have a point in common, then \(k=\)
- A \(\frac{2}{9}\)
- B \(-\frac{2}{9}\)
- C \(\frac{9}{2}\)
- D 0
Answer & Solution
Correct Answer
(C) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
Given line is \[ \frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}=\lambda \] So, \((x, y, z)\) is \((2 \lambda+1,3 \lambda-1,4 \lambda+1)\) and this point is lies on given line. This point also lies on line. \[ \frac{x-3}{1}=\frac{y-k}{2}=\frac{z}{1} \] So, this point satisfies…
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