AP EAMCET · Maths · Circle
Find the maximum distance of the point \(K(10,7)\) from the circle \(x^2+y^2-4 x-2 y-20=0\)
- A 25
- B 10
- C 15
- D 5
Answer & Solution
Correct Answer
(C) 15
Step-by-step Solution
Detailed explanation
Equation of given circle is \(\begin{aligned} & x^2+y^2-4 x-2 y-20 & =0 \\ \Rightarrow & (x-2)^2+(y-1)^2 & =25 \end{aligned}\) Having centre \(C(2,1)\) and radius \(r=5\) \(\therefore\) The maximum distance of the point \(K(10,7)\) from the given circle is \(C K+r\)…
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