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AP EAMCET · Maths · Permutation Combination

The number of ways of dividing 200 dissimilar things into 10 groups each containing 20 elements is

  1. A \((200) ! /(201)^{20} \cdot 10 !\)
  2. B \((200) ! /(10 !)^{10} \cdot 20 !\)
  3. C \((200) ! /(20 !)^{10} \cdot 10 !\)
  4. D \((200) ! /(10 !)^{20} \cdot 20 !\)
Verified Solution

Answer & Solution

Correct Answer

(C) \((200) ! /(20 !)^{10} \cdot 10 !\)

Step-by-step Solution

Detailed explanation

\(\because\) Division of \(m n\) objects into \(m n\) groups of equal size is done by \(\frac{(m n) !}{(n !)^m(m !)}\) Similarly, we have \(m n=200 \Rightarrow n=20, m=10\) \(\therefore\) Number of ways \(=\frac{(200) !}{(20 !)^{10},(10 !)}\)
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