AP EAMCET · Maths · Vector Algebra
Let \(2 \overline{\mathrm{i}}-\overline{\mathrm{j}}-\overline{\mathrm{k}}, 5 \overline{\mathrm{i}}+\overline{\mathrm{j}}-2 \overline{\mathrm{k}},-13 \overline{\mathrm{i}}-11 \overline{\mathrm{j}}+4 \overline{\mathrm{k}}\) be the position vectors of three points
A, \(\mathrm{B}, \mathrm{C}\) respectively. If \(\overline{\mathrm{AB}}=\lambda \overline{\mathrm{BC}}\) and \(\overline{\mathrm{AC}}=\mu \overline{\mathrm{CB}}\), then \(\lambda+\mu=\)
- A \(1\)
- B \(-1\)
- C \(2\)
- D \(-2\)
Answer & Solution
Correct Answer
(B) \(-1\)
Step-by-step Solution
Detailed explanation
\( \overline{\mathrm{AB}} = (5-2)\overline{\mathrm{i}} + (1-(-1))\overline{\mathrm{j}} + (-2-(-1))\overline{\mathrm{k}} = 3\overline{\mathrm{i}} + 2\overline{\mathrm{j}} - \overline{\mathrm{k}} \)…
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