AP EAMCET · Chemistry · Some Basic Concepts of Chemistry
The vapors of \(1 \mathrm{~g}\) of an element occupy \(2.5625 \mathrm{~L}\) exerting a pressure of \(0.5 \mathrm{~atm}\) at \(1000 \mathrm{~K}\). What is the molar mass (in \(\mathrm{g} \mathrm{mol}^{-1}\) ) of the element?
(Assume vapors follow ideal gas equation Given \(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\) )
- A \(64\)
- B \(16\)
- C \(32\)
- D \(128\)
Answer & Solution
Correct Answer
(A) \(64\)
Step-by-step Solution
Detailed explanation
\(\mathrm{PV}=\mathrm{nRT}=\frac{\mathrm{m}}{\mathrm{M}} \mathrm{RT} \Rightarrow \mathrm{M}=\frac{\mathrm{mRT}}{\mathrm{PV}}\) \(=\frac{(1)(0.082)(1000)}{(0.5)(2.5625)}=64 \mathrm{~g} \mathrm{~mol}^{-1}\).
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