AP EAMCET · PHYSICS · Magnetic Properties of Matter
A deflection magnetometer is adjusted and a magnet of magnetic moment \(M\) is placed on it in the usual manner and the observed deflection is \(\theta\). The period of oscillation of the needle before settling of the deflection is \(T\). When the magnet is removed, the period of oscillation of the needle is \(T_0\) before settling to \(0^{\circ}-0^{\circ}\). If the earth's induced magnetic field is \(B_H\), the relation between \(T\) and \(T_0\) is
- A \(T^2=T_0^2 \cos \theta\)
- B \(T^2=\frac{T_0^2}{\cos \theta}\)
- C \(T=T_0 \cos \theta\)
- D \(T=\frac{T_0}{\cos \theta}\)
Answer & Solution
Correct Answer
(A) \(T^2=T_0^2 \cos \theta\)
Step-by-step Solution
Detailed explanation
In deflection magnetometer, field due to magnet \(F\) and horizontal component \(B_H\) of earth's field are perpendicular to each other. \(\therefore\) Net field is \(\sqrt{F^2+B_H^2}\) So the time period \(T=2 \pi \sqrt{\frac{1}{M \sqrt{F^2+B_H}}}\) When magnet is removed…
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