AP EAMCET · Maths · Parabola
If the normal chord draw n at the point \(\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right)\) to the parabola \(\mathrm{y}^2=15 \mathrm{x}\) subtends an angle \(\theta\) at the vertex of the parabola, then \(\sin \frac{\theta}{3}+\cos \frac{2 \theta}{3}-\sec \frac{4 \theta}{3}=\)
- A \(0\)
- B \(3\)
- C \(1\)
- D \(2\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(y^2=15x \implies 4a=15 \implies a=\frac{15}{4}\) \(P_1\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right) = (at_1^2, 2at_1) \implies 2 \cdot \frac{15}{4} t_1 = \frac{15}{\sqrt{2}} \implies t_1 = \sqrt{2}\) \(t_2 = -t_1 - \frac{2}{t_1} = -\sqrt{2} - \frac{2}{\sqrt{2}} = -2\sqrt{2}\)…
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