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AP EAMCET · Maths · Parabola

If the normal chord draw n at the point \(\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right)\) to the parabola \(\mathrm{y}^2=15 \mathrm{x}\) subtends an angle \(\theta\) at the vertex of the parabola, then \(\sin \frac{\theta}{3}+\cos \frac{2 \theta}{3}-\sec \frac{4 \theta}{3}=\)

  1. A \(0\)
  2. B \(3\)
  3. C \(1\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(3\)

Step-by-step Solution

Detailed explanation

\(y^2=15x \implies 4a=15 \implies a=\frac{15}{4}\) \(P_1\left(\frac{15}{2}, \frac{15}{\sqrt{2}}\right) = (at_1^2, 2at_1) \implies 2 \cdot \frac{15}{4} t_1 = \frac{15}{\sqrt{2}} \implies t_1 = \sqrt{2}\) \(t_2 = -t_1 - \frac{2}{t_1} = -\sqrt{2} - \frac{2}{\sqrt{2}} = -2\sqrt{2}\)…