AP EAMCET · Maths · Differentiation
If \(y=\tan ^{-1}\left(\frac{2-3 \sin x}{3-2 \sin x}\right)\) then \(\frac{d y}{d x}=\)
- A \(\frac{(3-2 \sin x)^2}{13 \sin ^2 x-24 \sin x+13}\)
- B \(\frac{-5 \cos x}{13 \sin ^2 x-24 \sin x+13}\)
- C \(\frac{5 \sin x}{13 \sin ^2 x-24 \sin x+13}\)
- D \(\frac{-5 \sin x}{13 \sin ^2 x-24 \sin x+13}\)
Answer & Solution
Correct Answer
(B) \(\frac{-5 \cos x}{13 \sin ^2 x-24 \sin x+13}\)
Step-by-step Solution
Detailed explanation
Given, \(y=\tan ^{-1}\left(\frac{2-3 \sin x}{3-2 \sin x}\right)\) Now, \(\frac{d y}{d x}=\frac{d}{d x}\left(\tan ^{-1}\left(\frac{2-3 \sin x}{3-2 \sin x}\right)\right)\)…
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