AP EAMCET · PHYSICS · Thermodynamics
The total internal energy of 2 moles of a monotomic gas at a temperature \(27^{\circ} \mathrm{C}\) is U . The total internal energy of 3 moles of a diatomic gas at a temperature \(127^{\circ} \mathrm{C}\) is
- A U
- B \(\frac{10 \mathrm{U}}{3}\)
- C 2 U
- D \(\frac{2 U}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{10 \mathrm{U}}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{n}_1=2\) moles, \(\mathrm{T}_1=27^{\circ} \mathrm{c}=300 \mathrm{~K}\) For monoatomic gas, \(f_1=3\) \(\therefore \quad \mathrm{U}=\frac{\mathrm{n}_1 \mathrm{f}_1 \mathrm{RT}_1}{2}=\frac{2 \times 3 \times \mathrm{R} \times 300}{2}=900 \mathrm{R}\) For diatomic gas,…
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