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AP EAMCET · Maths · Straight Lines

A line \(L_1\) passing through the point of intersection of the lines \(x-2 y+3=0\) and \(2 x-y=0\) is parallel to the Line \(L_2\). If \(L_2\) passes through origin and also through the point of intersection of the lines \(3 x-y+2=0\) and \(x-3 y-2=0\), then the distance between the lines \(\mathrm{L}_1\) and \(\mathrm{L}_2\) is

  1. A \(\frac{1}{\sqrt{2}}\)
  2. B \(\sqrt{2}\)
  3. C \(\sqrt{5}\)
  4. D \(\frac{1}{\sqrt{5}}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{1}{\sqrt{2}}\)

Step-by-step Solution

Detailed explanation

Intersection of \(3x-y+2=0\) and \(x-3y-2=0\): \((x,y)=(-1,-1)\) Equation of \(L_2\) (through \((0,0)\) and \((-1,-1)\)): \(y=x \implies x-y=0\) Slope of \(L_2\) is \(m_2=1\) Intersection of \(x-2y+3=0\) and \(2x-y=0\): \((x,y)=(1,2)\) Equation of \(L_1\) (through \((1,2)\)…