AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure
The correct order of bond angles of the following is
\(\begin{array}{cccc}\mathrm{H}_2 \mathrm{O} & \mathrm{NH}_3 & \mathrm{CH}_4 & \mathrm{SO}_2 \\ \text { I } & \text { II } & \text { III } & \text { IV }\end{array}\)
- A IV \(>\) III \(>\) II \(>\) I
- B IV \(>\) III \(>\) I \(>\) II
- C I \(>\) II \(>\) III \(>\) IV
- D I \(>\) II \(>\) IV \(>\) III
Answer & Solution
Correct Answer
(A) IV \(>\) III \(>\) II \(>\) I
Step-by-step Solution
Detailed explanation
The bond angles are determined on the basis of hybridization of the central atom and the number of lone pairs and bond pairs that cause the repulsion and affect the bond angle. Thus, bond angle varies as IV \(>\) III \(>\) II \(>\) I.
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