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AP EAMCET · Maths · Sequences and Series

If \(x=\frac{2}{5}+\frac{1 \cdot 3}{2 !}\left(\frac{2}{5}\right)^2+\frac{1 \cdot 3 \cdot 5}{3 !}\left(\frac{2}{5}\right)^3+\ldots\), then \(x+\frac{1}{x}=\)

  1. A \(\frac{1+\sqrt{5}}{4}\)
  2. B 3
  3. C \(\frac{5 \sqrt{5}+3}{4}\)
  4. D \(\frac{5 \sqrt{5}-3}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{5 \sqrt{5}-3}{4}\)

Step-by-step Solution

Detailed explanation

Let \(x=(1+y)^n-1=n y\)…