AP EAMCET · Maths · Sequences and Series
If \(x=\frac{2}{5}+\frac{1 \cdot 3}{2 !}\left(\frac{2}{5}\right)^2+\frac{1 \cdot 3 \cdot 5}{3 !}\left(\frac{2}{5}\right)^3+\ldots\), then \(x+\frac{1}{x}=\)
- A \(\frac{1+\sqrt{5}}{4}\)
- B 3
- C \(\frac{5 \sqrt{5}+3}{4}\)
- D \(\frac{5 \sqrt{5}-3}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{5 \sqrt{5}-3}{4}\)
Step-by-step Solution
Detailed explanation
Let \(x=(1+y)^n-1=n y\)…
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