AP EAMCET · Maths · Application of Derivatives
Tangent at any point \(\theta\) on the curve \(x=35 \sec \theta y=35 \tan \theta\) is
- A \(y \sin \theta=x+35 \cos \theta\)
- B \(y \sin \theta=x-35 \cos \theta\)
- C \(y \cos \theta=x-35 \sin \theta\)
- D \(y \cos \theta=x+35 \sin \theta\)
Answer & Solution
Correct Answer
(B) \(y \sin \theta=x-35 \cos \theta\)
Step-by-step Solution
Detailed explanation
Given, \(x=35 \sec \theta\) \[ \begin{gathered} y=35 \tan \theta \\ \therefore \text { Point } P=(35 \sec \theta, 35 \tan \theta) \\ \text { Differentiate Eq. (i) w.r.to ' } \theta \text { ' } \\ \qquad \frac{d x}{d \theta}=35(\sec \theta \cdot \tan \theta) \end{gathered} \]…
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