AP EAMCET · Maths · Probability
Out of first 5 consecutive natural numbers, if two different numbers x and y are chosen at random, then the probability that \(x^4-y^4\) is divisible by 5 is
- A \(\frac{2}{5}\)
- B \(\frac{4}{5}\)
- C \(\frac{3}{5}\)
- D \(\frac{1}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{3}{5}\)
Step-by-step Solution
Detailed explanation
\(\because\) We know, if two numbers \(x\) and \(y\) are choosen at random without replacement from the set \(\{1,2,3,4, \ldots .\). \(5 K\}\), then the probability that \(x^4-y^4\) is divisible by 5 is \(\frac{17 K-5}{5(5 K-1)}\)…
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