AP EAMCET · Maths · Differential Equations
The general solution of the differential equation is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(B)
Step-by-step Solution
Detailed explanation
tanydx+(sec2y)(tanx)dy=0 dydx=-tanysec2ytanx On integrating, we get ∫sec2ydytany=∫-cotxdx ln(tany)=-ln(sinx)+c sinxtany=c1
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