AP EAMCET · Maths · Three Dimensional Geometry
Find the equation of the plane which passes through the points \((0,1,2)\) and \((-1,0,3)\) and is perpendicular to the plane \(2 x+3 y+z=5\).
- A \(3 x-4 y+18 z+32=0\)
- B \(3 x+4 y-18 z+32=0\)
- C \(4 x+3 y-z+1=0\)
- D \(4 x-3 y+z+1=0\)
Answer & Solution
Correct Answer
(D) \(4 x-3 y+z+1=0\)
Step-by-step Solution
Detailed explanation
Since, we know that the equation of plane passing through a point \(\left(x_1, y_1, z_1\right)\) is \(A\left(x-x_1\right)+B\left(y-y_1\right)+C\left(z-z_1\right)=0\) Equation of plane passing through \((0,1,2)\) is \(A(x-0)+B(y-1)+C(z-2)=0\) ...(i) \(\because\) Plane (i) passes…
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