AP EAMCET · Maths · Three Dimensional Geometry
If the vertices of a \(\triangle A B C\) are \(A=(2,3,5)\), \(B=(-1,3,2), C=(3,5,-2)\), then the area of the \(\triangle A B C\) (in sq. units) is
- A \(6 \sqrt{2}\)
- B \(8 \sqrt{3}\)
- C \(9 \sqrt{2}\)
- D \(8 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(9 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
The vertices of \(\triangle A B C\) are…
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