AP EAMCET · Maths · Circle
Consider the family of circles \(x^2+y^2-2 x-2 \lambda y-8=0\) which passes through two fixed points \(A\) and \(B\) distance between them is
- A 4
- B \(4 \sqrt{2}\)
- C 6
- D 8
Answer & Solution
Correct Answer
(C) 6
Step-by-step Solution
Detailed explanation
\(\begin{aligned} x^2+y^2-2 x-2 \lambda y-8 & =0 \\ \left(x^2+y^2-2 x-8\right)-\lambda(2 y) & =0 \\ x^2+y^2-2 x-8 & =0 \text { and } 2 y=0 \Rightarrow y=0 \\ x^2-2 x-8 & =0 \end{aligned}\) Distance between points \(A, B=\left|x_1-x_2\right|\)…
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