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AP EAMCET · PHYSICS · Mechanical Properties of Fluids

A liquid drop of diameter D splits into 3375 small identical drops. If S is the surface tension of the liquid, then the change in the surface energy in the process is

  1. A \(44 D^2 S\)
  2. B \(44 \pi D^2 S\)
  3. C \(56 \mathrm{D}^2 \mathrm{~S}\)
  4. D \(56 \pi D^2 S\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(44 D^2 S\)

Step-by-step Solution

Detailed explanation

\( \frac{4}{3} \pi (D/2)^3 = 3375 \times \frac{4}{3} \pi r^3 \) \( (D/2)^3 = 15^3 r^3 \Rightarrow D/2 = 15r \Rightarrow r = D/30 \) \( A_{initial} = 4 \pi (D/2)^2 = \pi D^2 \) \( A_{final} = 3375 \times 4 \pi (D/30)^2 = 3375 \times 4 \pi \frac{D^2}{900} = 15 \pi D^2 \)…