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AP EAMCET · Maths · Probability

It is observed that there will be 25 blood specimens of normal persons, if 100 blood samples are tested. If 10 specimens are sent to a laboratory for testing, then the probability of having at least two specimens of normal persons is

  1. A \(1-\frac{13}{4}\left(\frac{3}{4}\right)^{10}\)
  2. B \(1-\frac{13}{4}\left(\frac{3}{4}\right)^9\)
  3. C \(1-10\left(\frac{3}{4}\right)^{10}\)
  4. D \(1-\left(\frac{3}{4}\right)^{10}-10\left(\frac{3}{4}\right)^9 \frac{1}{4}-45\left(\frac{3}{4}\right)^8\left(\frac{1}{4}\right)^2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1-\frac{13}{4}\left(\frac{3}{4}\right)^9\)

Step-by-step Solution

Detailed explanation

The probability of selecting a normal specimen from a pool of 100 blood samples is \(\frac{25}{100}=\frac{1}{4}\) \[ \therefore \mathrm{P}=\frac{1}{4} \] \[ q=1-\frac{1}{4}=\frac{3}{4} \] No. of trials \(=\mathrm{n}=10\)…