AP EAMCET · Maths · Quadratic Equation
If the product of the roots of the equation \(x^2+4 k x+12 e^{3 \log k}-1=0,(k>0)\) is 323 , then the sum of its roots is
- A \(9 k\)
- B 12
- C -12
- D \(-16 k\)
Answer & Solution
Correct Answer
(C) -12
Step-by-step Solution
Detailed explanation
Given quadratic equation is \(x^2+4 k x+12 e^{3 \log k}-1=0\) According to given information , Product of the roots \(=323\) \(\begin{aligned} & \Rightarrow \quad 12 e^{3 \log k}-1=323 \\ & \Rightarrow \quad 12 k^3=324 \Rightarrow k^3=27 \Rightarrow k=3 \end{aligned}\) So, sum…
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