AP EAMCET · Maths · Straight Lines
The equations of the perpendicular bisectors of the sides AB and AC of \(\triangle \mathrm{ABC}\) are \(x-y+5=0\) and \(x+2 y=0\) respectively. If the coordinates of \(A\) are \((1,-2)\), then the equation of the line \(B C\) is
- A \(14 x+23 y-40=0\)
- B \(13 x-9 y-14=0\)
- C \(9 x-14 y-25=0\)
- D \(8 x+15 y-30=0\)
Answer & Solution
Correct Answer
(A) \(14 x+23 y-40=0\)
Step-by-step Solution
Detailed explanation
\(\because A B\) line is perpendicular to \(E O\) and passes through vertex \(A\), equation of \(A B\) is \(x+y+1=0\) Co-ordinates of \(E=\left(\frac{x_1+1}{2}, \frac{y_1-2}{2}\right)\) which is also intersection point of \(A B\) with…
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