AP EAMCET · Maths · Straight Lines
In \(\triangle \mathrm{ABC}\), if \(\mathrm{A}=(1,2)\) and the equations of the medians through \(B\) and \(C\) are \(x+y=5\) and \(x=4\) respectively, then the area of \(\triangle \mathrm{ABC}\) is
- A \(12\)
- B \(9\)
- C \(4\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(9\)
Step-by-step Solution
Detailed explanation
\(\mathrm{OC} \& \mathrm{OB}\) the equations of medians respectively and point \(\mathrm{O}\) is the centroid. \(\because\) Intersection OC \& OB is centroid. Solving \(x+y=5 \& x=4\), we get the centroid as \((4,1)\). Let the coordinate of point \(C=(4, a)\) and coordinate of…
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