AP EAMCET · PHYSICS · Mechanical Properties of Fluids
A liquid drop of density \(\rho\) is floating half immersed in a liquid of surface tension \(S\) and density \(\frac{\rho}{2}\). If the surface tension \(S\) of the liquid is numerically equal to 10 times of acceleration due to gravity, then the diameter of the drop is:
- A \(\sqrt{\frac{20}{\rho}}\)
- B \(\sqrt{\frac{80}{\rho}}\)
- C \(\sqrt{\frac{60}{\rho}}\)
- D \(\sqrt{\frac{40}{\rho}}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{\frac{80}{\rho}}\)
Step-by-step Solution
Detailed explanation
A figure given here, shows a liquid drop half immersed in a liquid, where density of drop, \(\rho_d=\rho\), density of liquid, \(\rho_L=\frac{\rho}{2}\) and surface tension, \(T=10 \mathrm{~g}\). Force acting on the drop due to surface tension, \(F=T l=\log (\pi D)\) ...(i) The…
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