AP EAMCET · Maths · Straight Lines
If the origin is shifted to remove the first degree terms from the equation \(2 x^2-3 y^2+4 x y+4 x+4 y-14=0\) then, with respect to this new co-ordinate system, the transformed equation of \(x^2+y^2-3 x y+4 y+3=0\) is
- A \(x^2+y^2-3 x y-2 x+y+6=0\)
- B \(x^2+y^2-3 x y-2 x+7 y+3=0\)
- C \(x^2+y^2-3 x y-2 x+y+4=0\)
- D \(x^2+y^2-3 x y-2 x+7 y+4=0\)
Answer & Solution
Correct Answer
(D) \(x^2+y^2-3 x y-2 x+7 y+4=0\)
Step-by-step Solution
Detailed explanation
\(2 x^2-3 y^2+4 x y+4 x+y-14=0\) Let \(x=\mathrm{X}+h, y=\mathrm{Y}+k\) Then \(2(\mathrm{X}+\mathrm{h})^2-3(\mathrm{Y}+k)^2+4(\mathrm{X}+\mathrm{h})(\mathrm{Y}+k)+4(\mathrm{X}+\mathrm{h})\) \(+4(\mathrm{Y}+k)-14=0\)…
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