AP EAMCET · Maths · Pair of Lines
Suppose \(A\) and \(B\) are the points at which the line \(x+y-\lambda=0\) meets the pair of straight lines \(x^2+y^2-2 x-4 y+2=0\). If \(\angle A O B=90^{\circ}\), then a value of \(\lambda\) is
- A \(2\)
- B \(3\)
- C \(4\)
- D \(0\)
Answer & Solution
Correct Answer
(A) \(2\)
Step-by-step Solution
Detailed explanation
Given, line is \(x+y-\lambda=0\) \(\Rightarrow \quad x+y=\lambda\) \(\Rightarrow \quad \frac{x+y}{\lambda}=1\)...(i) and pair of straight lines is \(x^2+y^2-2 x-4 y+2=0\) We will make homogeneous of the above line. \(x^2+y^2-2 x(\mathrm{l})-4 y(\mathrm{l})+2(\mathrm{l})^2=0\)…
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