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AP EAMCET · Maths · Functions

If \(x\) is real, then the range of \(\frac{x^2+2 x+1}{x^2+2 x+7}\) is

  1. A \([0,1)\)
  2. B \((-\infty, 0) \cup(1, \infty)\)
  3. C \((0,1)\)
  4. D \(R\)
Verified Solution

Answer & Solution

Correct Answer

(A) \([0,1)\)

Step-by-step Solution

Detailed explanation

\begin{array}{lc} \text {} & \text { Let } \frac{x^2+2 x+1}{x^2+2 x+7}=y, \\ \because & y \neq 1 \\ \Rightarrow & (y-1) x^2+2(y-1) x+(7 y-1)=0 \\ \because & x \in R \\ \text { so, } & D \geq 0 \\ \Rightarrow & 4(y-1)^2-4(y-1)(7 y-1) \geq 0 \\ \Rightarrow & (y-1)[y-1-7 y+1] \geq…

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