AP EAMCET · Maths · Circle
If the line \(x+2 y-5=0\) and \(3 x-y-1=0\) denote two diameters of a circle of radius 5 units, then the equation of the circle is
- A \(x^2+y^2-2 x+4 y-20=0\)
- B \(x^2+y^2-2 x-4 y-20=0\)
- C \(x^2+y^2+2 x-4 y+20=0\)
- D \(x^2+y^2+2 x+4 y+20=0\)
Answer & Solution
Correct Answer
(B) \(x^2+y^2-2 x-4 y-20=0\)
Step-by-step Solution
Detailed explanation
Equation of diameters of the circle, x + 2y − 5 = 0 … (i) 3x − y − 1 = 0 … (ii) Since, intersection of lines (i) and (ii) is the centre of the circle. On solving Eqs. (i) and (ii), we get x = 1 and y = 2 \(\therefore\) Centre \(=(1,2)\) and radius \(=5\) \(\therefore\) Equation…
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