AP EAMCET · Maths · Definite Integration
\(\int_0^\pi \frac{x \tan x}{\sec x+\tan x} d x\) is equal to
- A \(\frac{\pi(\pi-2)}{2}\)
- B \(\frac{\pi+2}{2}\)
- C \(\frac{\pi(\pi+2)}{2}\)
- D \(\frac{\pi-2}{2}\)
Answer & Solution
Correct Answer
(A) \(\frac{\pi(\pi-2)}{2}\)
Step-by-step Solution
Detailed explanation
\(\int_0^\pi \frac{x \tan x}{\sec x+\tan x} d x\) Let \(I=\int_0^\pi \frac{x \tan x}{\sec x+\tan x} d x...(i)\)…
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