AP EAMCET · Chemistry · d and f Block Elements

The magnetic moment of ${Fe}^{2 +}$ is $B . M .$

A $3.87$
B $0$
C $4.9$
D $1.73$

Verified Solution

Answer & Solution

Correct Answer

(C) $4.9$

Step-by-step Solution

Detailed explanation

We know μ = nn+2 where, n is the number of unpaired electrons The electronic configuration of Fe2+ = Ar3d64s0 According to the Aufbau's principal the unpaired electrons present in Fe2+ is 4 Thus,…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Match the following.

List - $I$		List - $II$
$(A)$	Addition polymer	$(I)$	Bakelite
$(B)$	Condensation polymer	$(II)$	$2$ -methyl- $1, 3$ -butadiene
$(C)$	Acrilan	$(III)$	$2, 3$ -dimethyl- $1, 3$ -butadiene
$(D)$	Rubber	$(IV)$	Vinyl cyanide
		$(V)$	Polythene

The correct answer is:

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(A)	Isothermal process	(i)	$q = ∆ U$
(B)	Adiabatic process	(ii)	$W = - P \times ΔV$
(C)	Isobaric process	(iii)	$W = ∆ U$
(D)	Isochoric process	(iv)	$W = - nRTln (\frac{V_{f}}{V_{i}})$

The magnetic moment of Fe2+ is B.M.

Step-by-step Solution

The magnetic moment of ${Fe}^{2 +}$ is $B . M .$