AP EAMCET · Maths · Probability
If \(X\) is a Poisson random variate with mean 3, then \(P(|X-3| < 2)=\)
- A \(\frac{9}{2 e^3}\)
- B \(\frac{99}{8 e^3}\)
- C \(\frac{3}{2 e^3}\)
- D \(\frac{1}{3 e^3}\)
Answer & Solution
Correct Answer
(B) \(\frac{99}{8 e^3}\)
Step-by-step Solution
Detailed explanation
For poisson distribution, \(P(X=k)=\frac{\lambda^k \cdot e^{-\lambda}}{k !}\)…
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