AP EAMCET · Maths · Limits
If \(\lim _{x \rightarrow 0} \frac{e^x-a-\log (1+x)}{\sin x}=0\) then \(a=\)
- A 2
- B 0
- C -1
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow 0} \frac{e^x-a-\log (1+x)}{\sin x}=0\) \(\Rightarrow \frac{e^0-a-\log 1}{\sin 0}=0 \Rightarrow \frac{1-a}{0}=0\) 0 or limit to exist \(a=1\)
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