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AP EAMCET · Maths · Vector Algebra

If \(\hat{i}\) is the position vector of the centroid \(G\) of triangle \(\mathrm{ABC}\) and \(2 \hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}}\) are respectively the position vectors of its vertices \(\mathrm{A}\) and \(\mathrm{B}\), then \(\mathrm{AG}^2+\mathrm{BG}^2+\mathrm{CG}^2=\)

  1. A \(77\)
  2. B \(74\)
  3. C \(86\)
  4. D \(83\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(74\)

Step-by-step Solution

Detailed explanation

Let vertex of \(c\) is \((x \hat{i}+y \hat{j}+z \hat{k})\) \(\begin{aligned} & \therefore \text { Centroid } G=i+0 \hat{j}+0 . \hat{k} \\ & =\frac{(2 \hat{i}+\hat{j}+\hat{k})+(2 \hat{i}+4 \hat{j}-4 \hat{k})+(x \hat{i}+y \hat{j}+z \hat{k})}{3} \end{aligned}\)…