AP EAMCET · Maths · Application of Derivatives
In a bank, the principal increases continuously at the rate of \(6 \%\) per year. Then the time required to double \(₹ 6000\) rupees is (in years)
- A \(\frac{50}{3} \log 2\)
- B \(\frac{50}{3} \log 6\)
- C \(\frac{50}{3} \log 3\)
- D \(\frac{50}{3} \log 12\)
Answer & Solution
Correct Answer
(A) \(\frac{50}{3} \log 2\)
Step-by-step Solution
Detailed explanation
According to given information, let the principal \(P=₹ 6000\) getting double in time ' \(t\) ' with rate of \(6 \%\) per year, so \(\frac{d P}{d t}=\frac{6}{100} P \Rightarrow \int_{6000}^{12000} \frac{d p}{P}=\frac{3}{50} \int_0^t d t\)…
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