AP EAMCET · Maths · Parabola
The perpendicular distance from the origin to the focal chord drawn through the point \((4,5)\) to the parabola \(y^2-4 y-3 x+7=0\) is
- A \(\frac{2}{5}\)
- B \(\frac{1}{\sqrt{2}}\)
- C \(\frac{1}{5}\)
- D \(1\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{5}\)
Step-by-step Solution
Detailed explanation
Given equation of parabola \(\begin{aligned} & y^2-4 y-3 x+7=0 \Rightarrow(y-2)^2=3(x-1) \\ & \Rightarrow(y-2)^2=4 \cdot \frac{3}{4}(x-1) \end{aligned}\) So focus is \(\left(\frac{3}{4}+1,2\right)=\left(\frac{7}{4}, 2\right)\) Now, equation of focal chord is…
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