AP EAMCET · Chemistry · Solid State
An element crystallising in fcc lattice has a density of \(8.92 \mathrm{~g} \mathrm{~cm}^{-3}\) and edge length of \(3.61 \times 10^{-8} \mathrm{~cm}\). What is the atomic weight of element? \(\left(N=6.022 \times 10^{23} \mathrm{~mol}^{-1}\right)\)
- A \(126.356 u\)
- B \(63.178 u\)
- C \(31.589 u\)
- D \(47.383 u\)
Answer & Solution
Correct Answer
(B) \(63.178 u\)
Step-by-step Solution
Detailed explanation
Given, \(d=8.92 \mathrm{~g} \mathrm{~cm}^{-3}\) (Edge length) \(a=3.61 \times 10^{-8} \mathrm{~cm}\) \(M=\) ? For fcc, \(Z=4\) \(d=\frac{Z \times M}{a^3 \times N}\) \(8.92=\frac{4 \times M}{\left(3.61 \times 10^{-8}\right)^3 \times 6.022 \times 10^{23}}\)…
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