AP EAMCET · Maths · Limits
If \(f(x)=\frac{e^{1 / x}-1}{e^{1 / x}+1}\), then
- A \(\lim _{x \rightarrow 0} f(x)=0\)
- B \(\lim _{x \rightarrow \infty} f(x)=1\)
- C \(\lim _{x \rightarrow 0} f(x)=-1\)
- D \(\lim _{x \rightarrow \infty} f(x)=0\)
Answer & Solution
Correct Answer
(D) \(\lim _{x \rightarrow \infty} f(x)=0\)
Step-by-step Solution
Detailed explanation
\(\lim _{x \rightarrow \infty} f(x)=\lim _{x \rightarrow 0} \frac{e^{\frac{1}{x}}-1}{e^{\frac{1}{x}}+1}\) \(\therefore \lim _{x \rightarrow \infty} f(x)=0\)
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