AP EAMCET · Maths · Differential Equations
The solution of the differential equation \(x^2(y+1) \frac{d y}{d x}+y^2(x+1)^2=0\), when \(y(1)=2\), is
- A \(\log \left|x^2 y\right|=\frac{2}{x}+\frac{1}{y}+x-1\)
- B \(\log \left|\frac{1}{4} x^2 y\right|=\frac{1}{x}+\frac{2}{y}+x-1\)
- C \(\log \left|\frac{1}{2} x^2 y\right|=\frac{1}{x}+\frac{1}{y}-x-\frac{1}{2}\)
- D \(\log \left|\frac{1}{3} x^2 y\right|=\frac{1}{x}+\frac{1}{y}-x+\frac{1}{2}\)
Answer & Solution
Correct Answer
(C) \(\log \left|\frac{1}{2} x^2 y\right|=\frac{1}{x}+\frac{1}{y}-x-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\int \left(\frac{y+1}{y^2}\right) dy = -\int \left(\frac{(x+1)^2}{x^2}\right) dx\) \(\int \left(\frac{1}{y} + \frac{1}{y^2}\right) dy = -\int \left(1 + \frac{2}{x} + \frac{1}{x^2}\right) dx\) \(\ln|y| - \frac{1}{y} = -x - 2\ln|x| + \frac{1}{x} + C\)…
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