AP EAMCET · PHYSICS · Kinetic Theory of Gases
An ideal gas is kept in a cylinder of volume \(3 \mathrm{~m}^3\) at a pressure of \(3 \times 10^5 \mathrm{~Pa}\). The energy of the gas is
- A \(13.5 \times 10^6 \mathrm{~J}\)
- B \(1.35 \times 10^5 \mathrm{~J}\)
- C \(13.5 \times 10^5 \mathrm{~J}\)
- D \(135 \times 10^6 \mathrm{~J}\)
Answer & Solution
Correct Answer
(C) \(13.5 \times 10^5 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
For ideal gas, \(V=3 \mathrm{~m}^3, \mathrm{P}=3 \times 10^5 \mathrm{pa}\) \(\therefore \quad\) The energy of the gas is \(\mathrm{E}=\frac{3}{2} \mathrm{pV}=\frac{3}{2} \times 3 \times 10^5 \times 3=13.5 \times 10^5 \mathrm{~J}\)
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