AP EAMCET · Maths · Circle
If \(x^2+y^2-4 x-2 y+5=0\) and \(x^2+y^2-6 x-4 y-3=\) 0 are members of a coaxial system of circles, then the centre of a point circle in the system is
- A \((-5,-6)\)
- B \((5,6)\)
- C \((3,5)\)
- D \((-8,-13)\)
Answer & Solution
Correct Answer
(A) \((-5,-6)\)
Step-by-step Solution
Detailed explanation
Equation of coaxial system: \(S_1 + \lambda S_2 = 0\) \((x^2+y^2-4 x-2 y+5) + \lambda (x^2+y^2-6 x-4 y-3) = 0\) \((1+\lambda)x^2 + (1+\lambda)y^2 - (4+6\lambda)x - (2+4\lambda)y + (5-3\lambda) = 0\)…
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