AP EAMCET · Maths · Parabola
The line \(y=6 x+1\) touches the parabola \(y^2=24 x\). The coordinates of a point \(P\) on this line, from which the tangent to \(y^2=24 x\) is perpendicular to the line \(y=6 x+1\), is
- A \((-1,-5)\)
- B \((-2,-11)\)
- C \((-6,-35)\)
- D \((-7,-41)\)
Answer & Solution
Correct Answer
(C) \((-6,-35)\)
Step-by-step Solution
Detailed explanation
Given, equation of line is y = 6x + 1 and equation of pa rab ola is \(y^2=24 x\). The locus of the point of intersection of perpendicular tangent to a parabola is its directrix. So, required point is the point of intersection of y = 6x + 1 and direc trix x = − 6. Hence, its…
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