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AP EAMCET · Maths · Quadratic Equation

If \(\frac{\mathrm{k}}{\mathrm{kx}+3}+\frac{3}{3 \mathrm{x}-\mathrm{k}}=\frac{12 \mathrm{x}+5}{(\mathrm{kx}+3)(3 \mathrm{x}-\mathrm{k})} \forall \mathrm{x} \in \mathrm{R}\)
\(-\left\{\frac{\{3\}}{\mathrm{k}}, \frac{\mathrm{k}}{3}\right\}\), then both the roots of the equation \(\mathrm{kx}^2-7 \mathrm{x}+3=0\) are

  1. A Rational numbers
  2. B Irrational numbers
  3. C Complex numbers
  4. D Integers
Verified Solution

Answer & Solution

Correct Answer

(A) Rational numbers

Step-by-step Solution

Detailed explanation

Given, \[ \begin{aligned} & \frac{k}{(k x+3)}+\frac{3}{(3 x-k)}=\frac{12 x+5}{(k x+3)(3 x-k)} \\ & \Rightarrow k(3 x-k)+3(k x+3)=12 x+5 \\ & \Rightarrow 6 x k-k^2+9=12 x+5 \end{aligned} \] Comparing both side, we get \[ \Rightarrow 6 k=12 \Rightarrow k=2 \] Hence,…