AP EAMCET · Maths · Straight Lines
\(\mathrm{P}(6,4)\) is a point on the line \(\mathrm{x}-\mathrm{y}-2=0\). If \(\mathrm{A}(\alpha, \beta)\) and \(\mathrm{B}(\gamma, \delta)\) are two points on this line lying on either side of \(P\) at a distance of 4 units from \(P\), then \(\alpha^2+\beta^2+\gamma^2+\delta^2=\)
- A \(136\)
- B \(\frac{85}{\sqrt{2}}\)
- C \(23+\frac{5}{\sqrt{2}}\)
- D \(52\)
Answer & Solution
Correct Answer
(A) \(136\)
Step-by-step Solution
Detailed explanation
\(A(\alpha, \beta) = \left(6+4\frac{1}{\sqrt{2}}, 4+4\frac{1}{\sqrt{2}}\right) = \left(6+2\sqrt{2}, 4+2\sqrt{2}\right)\) \(B(\gamma, \delta) = \left(6-4\frac{1}{\sqrt{2}}, 4-4\frac{1}{\sqrt{2}}\right) = \left(6-2\sqrt{2}, 4-2\sqrt{2}\right)\)…
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