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AP EAMCET · PHYSICS · Laws of Motion

A bead of mass \(100 \mathrm{~g}\) is attached to one end of a spring of natural length \(L\) and spring constant \(k=\frac{(\sqrt{3}+1) m g}{L}\), where \(m\) is the mass of bead. The other end of the spring is fixed at point \(A\) on a smooth vertical ring of radius \(R\) as shown in the figure. The normal reaction at \(B\) just after it is released to move is (take, \(g=9.8 \mathrm{~ms}^{-2}\) )

  1. A \(1.73 \mathrm{~N}\)
  2. B ,
    \(2.23 \mathrm{~N}\)
  3. C \(2.44 \mathrm{~N}\)
  4. D \(2.55 \mathrm{~N}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2.55 \mathrm{~N}\)

Step-by-step Solution

Detailed explanation

Normal reaction \(=\) Resultant of spring force \(k x\) and weight \(\mathrm{mg}\). \[ =\sqrt{\left(k^2 x^2+m^2 g^2\right)}=2.55 \mathrm{~N} \]