AP EAMCET · Maths · Ellipse
The angle between the tangents drawn from the point \((1,2)\) to the ellipse \(3 x^2+2 y^2=5\) is
- A \(\tan ^{-1}\left(\frac{12 \sqrt{5}}{5}\right)\)
- B \(\tan ^{-1}\left(\frac{12 \sqrt{5}}{13}\right)\)
- C \(\frac{\pi}{4}\)
- D \(-\frac{\pi}{4}\)
Answer & Solution
Correct Answer
(A) \(\tan ^{-1}\left(\frac{12 \sqrt{5}}{5}\right)\)
Step-by-step Solution
Detailed explanation
Given Ellipse, \[ 3 x^2+2 y^2-5=0 \] Then, equations of pairs of tangents drawn to the ellipse \(S\) from the point \((1,2)\).…
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