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AP EAMCET · Maths · Continuity and Differentiability

If \(a\) and \(b(a>b)\) are points of discontinuity of the function
\[
f(x)=\left\{\begin{array}{ccc}
3-2 x^2, & \text { for } & x \leq 0 \\
2 x+3, & \text { for } & 0 < x \leq 1 \\
2 x^2-3 x, & \text { for } & 1 < x < 2 \\
2 x-3, & \text { for } & 2 \leq x < 3 \\
|x|, & \text { for } & x \geq 3
\end{array}\right.
\]
then \(3 a-b=\)

  1. A 3
  2. B 7
  3. C 5
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(C) 5

Step-by-step Solution

Detailed explanation

Since, LHL (at \(x=1)=5\) and RHL (at \(x=1\) ) \(=-1\), so function is discontinuous at \(x=1\), And LHL (at \(x=2)=2\) and RHL (at \(x=2\) ) \(=1\), so function is discontinuous at \(x=2\). So, \(a=2\) and \(b=1(\because a>b)\), \(\Rightarrow \quad 3 a-b=5\)