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AP EAMCET · Maths · Determinants

What is the value of abca-bb-cc-ab+cc+aa+b= ?

  1. A a3+b3+c3+3abc
  2. B a3+b3+c3-3abc
  3. C a3+b3+c3-6abc
  4. D a3+b3+c3+6abc
Verified Solution

Answer & Solution

Correct Answer

(B) a3+b3+c3-3abc

Step-by-step Solution

Detailed explanation

abca-bb-cc-ab+cc+aa+b  (R2→R2-R1) =abc-b-c-ab+cc+aa+b (R3→R3+R2) And taking out -1 As common -1abcbcacab Solving the determinant we get =-1[a(cb-a2)-b(b2-ac)+c(ab-c2)] =-1[3abc-a3-b3-c3] =a3+b3+c3-3abc