AP EAMCET · PHYSICS · Thermodynamics
A gas at \(37^{\circ} \mathrm{C}\) is compressed adiabatically to half of its volume, then the final temperature of the gas is
(Ratio of specific heat capacities of the gas is 1.5)
- A \(165.3^{\circ} \mathrm{C}\)
- B \(438.3^{\circ} \mathrm{C}\)
- C \(400^{\circ} \mathrm{C}\)
- D \(0^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(165.3^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
In an Adiabatic process, \(T V^{\gamma-1}=\) constant \[ \Rightarrow T_1 \cdot V_1^{\gamma-1}=T_2 V_2^{\gamma-1} \Rightarrow T_2=T_1\left(\frac{V_1}{V_2}\right)^{\gamma-1} \] Here, \(r=1.5, V_2=V_1 / 2\) and \(T_1=37^{\circ} \mathrm{C}=310.15 \mathrm{~K}\) So, final temperature…
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