AP EAMCET · Maths · Definite Integration
\(\int_0^{\pi / 2} e^{\sin x} \cdot \cos x d x=\)
- A \(1-e\)
- B \(1+e\)
- C \(e-1\)
- D \(e\)
Answer & Solution
Correct Answer
(C) \(e-1\)
Step-by-step Solution
Detailed explanation
\(I=\int_0^{\pi / 2} e^{\sin x} \cos x d x\) Put \(\sin x=t\), then at \(x=0, t=0\) and at \(x=\frac{\pi}{2}, t=1\) and \(\cos x d x=d t\) So, \(I=\int_0^1 e^t d t=\left[e^t\right]_0^1=e^1-1=e-1\)
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